Find the distance of the plane 2x – 3y + 4z – 6 = 0 from the origin.
The given equation of the plane is
2x – 3y + 4z – 6 = 0
Or, 2x – 3y + 4z = 6 …… (i)
Now,
Dividing (i) by , we get
, which is the normal form of the plane (i).
So, the length of the perpendicular from the origin to the plane =