In Fig. 6.20, DE || OQ and DF || OR. Show thatEF || QR.

Question

Philoid · Accepted Answer

Given that In triangle POQ, DE parallel to OQ

Hence,

(Basic proportionality theorem) (i)

Now,

Hence,

(Basic proportionality theorem) (ii)

From (i) and (ii), we get

Therefore,

EF is parallel to QR (Converse of basic proportionality theorem)