Find the principal values of each of the following:

Let us assume 2sin
= θ
We know sin![]()
∴ 2sin
= 2![]()
⇒ 2sin
= √2
∴ The question becomes sec–1(√2)
Now,
Let sec–1(√2) = y
⇒ sec y = √2
⇒ sec
= √2
The range of principal value of sec–1is [0, π ]–{
}
And sec
= √2
∴ The principal value of sec–1(2sin
) is
.