cosec–1(2cos
)
Let us assume 2cos
= θ
We know cos
= ![]()
∴ 2cos
= 2![]()
⇒ 2cos
= –1
∴ The question converts to cosec–1(–1)
Now,
cosec–1–1 = y
⇒ cosec y = –1
⇒ –cosec y = 1
⇒ –cosec
= 1
As we know cosec(–θ) = –cosecθ
∴ –cosec
= cosec ![]()
The range of principal value of cosec–1 is
–{0} and
cosec
= –1
Therefore, the principal value of cosec–1(2cos
) is
.