For the principal values, evaluate the following:

Let,
Sin–1
= y
⇒ sin y = ![]()
⇒ –sin y = ![]()
⇒ –sin ![]()
As we know sin(–θ) = –sinθ
∴ –sin
= sin ![]()
The range of principal value of sin–1 is
and sin ![]()
Therefore, the principal value of Sin–1
is
….(1)
Let,
cosec–1
= z
⇒ cosec z = ![]()
⇒ –cosec z = ![]()
⇒ –cosec ![]()
As we know cosec(–θ) = –cosecθ
∴ –cosec
= cosec ![]()
The range of principal value of cosec–1 is is
–{0} and
cosec ![]()
Therefore, the principal value of cosec–1
is
….(2)
From (1) and (2) we get
⇒ ![]()
= ![]()