Evaluate each of the following:
The value of sin
is 
∴ The question becomes sin–1
Let sin–1
= y
⇒ sin y = 
= sin
The range of principal value of sin–1 is 
and sin 
Therefore, the value of sin–1(sin
) is 
.
Alternate Solution:
sin–1(sin x) = x
Provided x ϵ 
∴ we can write sin–1(sin
) = 
1