Evaluate each of the following:
As sec(–θ) is sec(θ)
∴ sec = sec
The value of sec is –√2 .
Let sec–1(–√2) = y
⇒ sec y = –√2
= – sec = √2
= sec
= sec
The range of principal value of sec–1is [0, π]–{}
and sec = –√2.
Therefore, the value of sec–1sec is .