D, E and F are respectively the mid-points of sides AB, BC and CA of Δ ABC. Find the ratio of the areas of ΔDEF and Δ ABC
Given:

Because D, E and F are respectively the mid-points of sides AB, BC and CA of Δ ABC,
Therefore, From mid-point theorem,
DE || AC and DE =
AC
DF || BC and DF =
BC
EF || AC and EF =
AB
Now, In ΔBED and ΔBCD
∠BED =∠ BCA (Corresponding angles)
∠BDE = ∠BAC (Corresponding angles)
∠EBD = ∠CBA (Common angles)
Therefore,
ΔBED ~ ΔBCA (From the AAA similarity)

= ![]()
ar(ΔBED) =
ar(ΔBCA)
Similarly,
ar(ΔCFE) =
ar(ΔCBA)
And,
ar(ΔADF) =
ar(ΔABC)
Also,
ar(ΔDEF) = ar(ΔABC) – [ar(ΔBED) + ar(ΔCFE) + ar(ΔADF)]
ar(ΔDEF) = ar(ΔABC) – ![]()
=
ar(ΔABC)
= ![]()