D, E and F are respectively the mid-points of sides AB, BC and CA of Δ ABC. Find the ratio of the areas of ΔDEF and Δ ABC


Given:



Because D, E and F are respectively the mid-points of sides AB, BC and CA of Δ ABC,


Therefore, From mid-point theorem,


DE || AC and DE = AC


DF || BC and DF =  BC


EF || AC and EF = AB


Now, In ΔBED and ΔBCD


BED = BCA (Corresponding angles)


BDE = BAC (Corresponding angles)


EBD = CBA (Common angles)


Therefore,


ΔBED ~ ΔBCA (From the AAA similarity)



=


ar(ΔBED) = ar(ΔBCA)


Similarly,


ar(ΔCFE) = ar(ΔCBA)


And,


ar(ΔADF) = ar(ΔABC)


Also,


ar(ΔDEF) = ar(ΔABC) – [ar(ΔBED) + ar(ΔCFE) + ar(ΔADF)]


ar(ΔDEF) = ar(ΔABC) –


= ar(ΔABC)


=

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