ABC is an equilateral triangle of side 2a. Find each of its altitudes


Let AD be the altitude of the given equilateral triangle, ΔABC

We know that altitude bisects the opposite side


BD = DC = a



In triangle ADB,


ADB = 90O


Using Pythagoras theorem, we get


AD2 + DB2 = AB2


AD2 + a2 = (2a)2


AD2 + a2 = 4a2


AD2 = 3a2


AD = a


In an equilateral triangle, all the altitudes are equal in length.


Hence, the length of each altitude will be


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