ABC is an equilateral triangle of side 2a. Find each of its altitudes
Let AD be the altitude of the given equilateral triangle, ΔABC
We know that altitude bisects the opposite side
BD = DC = a
In triangle ADB,
∠ADB = 90O
Using Pythagoras theorem, we get
AD2 + DB2 = AB2
AD2 + a2 = (2a)2
AD2 + a2 = 4a2
AD2 = 3a2
AD = a
In an equilateral triangle, all the altitudes are equal in length.
Hence, the length of each altitude will be