A ladder 10 m long reaches a window 8 m above theground. Find the distance of the foot of the ladder from base of the wall
Let OA be the wall and AB be the ladder
By Pythagoras theorem,
AB2 = OA2 + BO2
(10)2 = (8)2 + OB2
100 = 64 + OB2
OB2 = 36
OB = 6 cm
Therefore, the distance of the foot of the ladder from the base of the wall is 6 m
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