Two poles of heights 6 m and 11 m stand on aplane ground. If the distance between the feetof the poles is 12 m, find the distance between their tops
Let CD and AB be the poles of height 11 m and 6 m
Therefore, CP = 11 - 6 = 5 m
From the figure, it can be observed that AP = 12m
Applying Pythagoras theorem for ΔAPC, we obtain
AP2 + PC2 = AC2
(12)2 + (5)2 = AC2
AC2 = (144 + 25)
AC2 = 169
AC = 13 m
Therefore, the distance between their tops is 13 m
13