In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that:
(i) Δ APC ~ Δ DPB

(ii) AP . PB = CP . DP

Question

In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that: (i) &#x394; APC ~ &#x394; DPB (ii) AP . PB = CP . DP

Philoid · Accepted Answer

(i) In triangle APC and DPB,

∠CAP = ∠BDP (Angles on the same side of a chord are equal)

∠APC = ∠DPB (Opposite angles)

Hence,

Δ APC ~ Δ DPB (By AAA similarity)

(ii) Since, the two triangles are similar

Hence,

Or,

AP * PB = CP * DP

Hence, proved

In Fig. 6.61, two chords AB and CD intersect each other at the point P. Prove that:(i) Δ APC ~ Δ DPB(ii) AP . PB = CP . DP