From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm2


Given:

Height (h) of the conical part = Height (h) of the cylindrical part = 2.4 cm


Diameter of the cylindrical part = 1.4 cm


Radius (r) of the cylindrical part = 0.7 cm


Slant height of the cylindrical part (l) =


=


=


= 2.5


Total surface area of the remaining solid will be


= CSA of cylindrical part + CSA of conical part + Area of cylindrical base


= 2πrh + πrl + πr2


= 2 * * 0.7 * 2.4 + * 0.7 * 2.5 + * 0.7 * 0.7


= 4.4 * 2.4 + 2.2 * 2.5 + 2.2 * 0.7


= 10.56 + 5.50 + 1.54


= 17.60 cm2


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