From a solid cylinder whose height is 2.4 cm and diameter 1.4 cm, a conical cavity of the same height and same diameter is hollowed out. Find the total surface area of the remaining solid to the nearest cm²

Given:

Height (h) of the conical part = Height (h) of the cylindrical part = 2.4 cm

Diameter of the cylindrical part = 1.4 cm

Radius (r) of the cylindrical part = 0.7 cm

Slant height of the cylindrical part (l) =

=

=

= 2.5

Total surface area of the remaining solid will be

= CSA of cylindrical part + CSA of conical part + Area of cylindrical base

= 2πrh + πrl + πr²

= 2 * * 0.7 * 2.4 + * 0.7 * 2.5 + * 0.7 * 0.7

= 4.4 * 2.4 + 2.2 * 2.5 + 2.2 * 0.7

= 10.56 + 5.50 + 1.54

= 17.60 cm²