The coach of a cricket team buys 3 bats and 6 balls for Rs 3900. Later, she buys another bat and 2 more balls of the same kind for Rs 1300. Represent this situation algebraically and geometrically.


Let cost of one bat = Rs. X

Let cost of one ball = Rs. Y


According to the question,


=


Dividing equation by 3.


=


=


Putting y = -1300 , 0 , 1300 we get,


X = 1300 – 2(-1300) = 1300+2600 = 3900


X = 1300 – 2(0) = 1300


X = 1300 – 2(1300) = 1300 – 2600 = -1300


X



3900



1300



-1300



Y



-1300



0



1300



She buys another bat and 2 more balls of the same kind for Rs.1300 (Given)


=


=


Putting y = -1300 , 0 , 1300 we get,


X = 1300 – 2(-1300) = 1300+2600 = 3900


X = 1300 – 2(0) = 1300


X = 1300 – 2(1300) = 1300 – 2600 = -1300


X



3900



1300



-1300



Y



-1300



0



1300



Algebric representation:


3x+6y = 3900………………..(i)


X+2y= 1300…………………..(ii)


Graphical Representation for first equation:



Graphical Representation for second equation:


Untitled.png


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