The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.


Let cost of each kg of apples = Rs. X

Let cost of each kg of grapes = Rs. Y


According to the question,


=


=


=


Putting y = 0, 80 , 160 we get,


X =


X=


X =


X



80



40



0



Y



0



80



160



Cost of 4 kg of apples and 2 kg of grapes is Rs. 300……………………………(Given)


So,


=


Dividing the equation by 2 , we get,


=


=


Putting y = 0, 50 , 100 we get,


Y = 150 – 2×0 = 150


Y = 150 – 2(50) = 150 – 100 = 50


Y = 150 – 2(100) = 150 – 200 = -50


X



0



50



100



Y



150



50



-50



Algebraic representation :


2x+y = 160 ………………(i)


4x+2y= 300……………..(ii)


Graphical representation :


Untitled...png


3
1