The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.

Question

Philoid · Accepted Answer

Let cost of each kg of apples = Rs. X

Let cost of each kg of grapes = Rs. Y

According to the question,

=

Putting y = 0, 80 , 160 we get,

X =

X=

X =

X	80	40	0
Y	0	80	160

Cost of 4 kg of apples and 2 kg of grapes is Rs. 300……………………………(Given)

So,

=

Dividing the equation by 2 , we get,

=

Putting y = 0, 50 , 100 we get,

Y = 150 – 2×0 = 150

Y = 150 – 2(50) = 150 – 100 = 50

Y = 150 – 2(100) = 150 – 200 = -50

X	0	50	100
Y	150	50	-50

Algebraic representation :

2x+y = 160 ………………(i)

4x+2y= 300……………..(ii)

Graphical representation :

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