Let ABC be a right triangle in which AB = 6 cm, BC = 8 cm and B = 90°. BD is theperpendicular from B on AC. The circle through B, C, D is drawn. Construct the tangents from A to this circle.


Steps of construction:


i. Draw a line segment AB = 6 cm.


 


ii. Draw a right angle at point B and then, BC = 8 cm.


 


iii. Now, draw a perpendicular BD to AC.


 


iv. We know: In a right triangle, hypotenuse is the diameter of circum circle


 


v. Considering BC as diameter, draw a circle passing through points B, C and D.


 


vi. Join A to O and taking AO as diameter, draw second circle.


 


vii. From point A, draw tangents AB and AP.


 


The final figure is obtained as shown below:



 

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