If and
then find λ, μ so that A2 = λ A + μ I
Given: ,
and A2 = λA + μI
So
Now, we will find the matrix for A2, we get
[as cij = ai1b1j + ai2b2j + … + ainbnj]
Now, we will find the matrix for λA, we get
But given, A2 = λA + μI
Substitute corresponding values from eqn(i) and (ii), we get
[as rij = aij + bij + cij],
And to satisfy the above condition of equality, the corresponding entries of the matrices should be equal
Hence, λ + 0 = 4 ⇒ λ = 4
And also, 2λ + μ = 7
Substituting the obtained value of λ in the above equation, we get
2(4) + μ = 7 ⇒ 8 + μ = 7 ⇒ μ = – 1
Therefore, the value of λ and μ are 4 and – 1 respectively