If and x2 = – 1, then show that (A + B)2 = A2 + B2.
Given,
and x2 = –1.
We need to prove (A + B)2 = A2 + B2.
Let us evaluate the LHS and the RHS one at a time.
To find the LHS, we will first calculate A + B.
We know (A + B)2 = (A + B)(A + B).
(∵ x2 = –1)
To find the RHS, we will first calculate A2 and B2.
We know A2 = A × A.
(∵ x2 = –1)
Similarly, we also have B2 = B × B.
Now, the RHS is A2 + B2.
Thus, (A + B)2 = A2 + B2.