The 17th term of an AP exceeds its 10th term by 7. Find the common difference.
Tenth and seventeenth terms of this AP can be given as follows:
a10 = a + 9d
a17 = a + 16d
Subtracting 10th term from 17th term, we get;
a + 16d – a – 9d = 7
7d = 7
d = 1