Prove the following identities:


L.H.S =


As |A| = |A|T


So,


If any two rows or columns of the determinant are interchanged, then determinant changes its sign



Apply C1C1 + C2 + C3



Taking (a + b + c) common from C1 we get,



Applying, R3R3 – 2R1



= – (a + b + c)[(b – c)(a + b – 2c) – (c – a)(c + a – 2b)]


= 3abc – a3 – b3 – c3


As, L.H.S = R.H.S, hence proved.


12
1