Prove the following identities:

Question

Philoid · Accepted Answer

Applying, C₁→C₁ + C₂ – 2C₃

Taking (a² + b² + c²), common, we get,

Applying R₂→R₂ – R₁ and R₃→R₃ – R₁, we get,

= (a² + b² + c²)(b – a)(c – a)[(b + a)( – b) – ( – c)(c + a)]

= (a² + b² + c²)(a – b)(c – a)(b – c)(a + b + c)

= R.H.S

Hence, proved.