Prove the following identities –


Let


Recall that the value of a determinant remains same if we apply the operation Ri Ri + kRj or Ci Ci + kCj.


Applying C2 C2 – pC1, we get




Applying C3 C3 – qC1, we get




Applying C3 C3 – pC2, we get




Applying C2 C2 – C1, we get




Applying C3 C3 – C1, we get




Expanding the determinant along R1, we have


Δ = 1[(1)(7) – (3)(2)] – 0 + 0


Δ = 7 – 6 = 1


Thus,


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