Prove the following identities –
Let
Recall that the value of a determinant remains same if we apply the operation Ri→ Ri + kRj or Ci→ Ci + kCj.
Applying R1→ R1 + R2, we get
Applying R1→ R1 + R3, we get
Taking the term (5x + 4) common from R1, we get
Applying C2→ C2 – C1, we get
Applying C3→ C3 – C1, we get
Expanding the determinant along R1, we have
Δ = (5x + 4)[(1)(4 – x)(4 – x)]
∴ Δ = (5x + 4)(4 – x)2
Thus,