Prove the following identities –


Let


Recall that the value of a determinant remains same if we apply the operation Ri Ri + kRj or Ci Ci + kCj.


Applying R1 R1 + R2, we get




Applying R1 R1 + R3, we get




Taking the term (3 + a) common from R1, we get



Applying C2 C2 – C1, we get




Applying C3 C3 – C1, we get




Expanding the determinant along R1, we have


Δ = (3 + a)(1)[(a)(a) – 0]


Δ = (3 + a)(a2)


Δ = a3 + 3a2


Thus,


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