Prove the following identities –


Let


Recall that the value of a determinant remains same if we apply the operation Ri Ri + kRj or Ci Ci + kCj.


Applying C1 C1 + C2, we get




Applying C1 C1 + C3, we get




Taking the term (a + x + y + z) common from C1, we get



Applying R2 R2 – R1, we get




Applying R3 R3 – R1, we get




Expanding the determinant along C1, we have


Δ = (a + x + y + z)(1)[(a)(a) – (0)(0)]


Δ = (a + x + y + z)(a)(a)


Δ = a2(a + x + y + z)


Thus,


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