Find the area of the triangle with vertices at the points:

(– 1, – 8), (– 2, – 3) and (3, 2)


Given: – Vertices of the triangle:


(– 1, – 8), (– 2, – 3) and (3, 2)


We know that,


If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now, substituting given value in above formula



Expanding along R1





sq.units


as area cannot be negative


Therefore, 15 sq.unit is the area


Thus area of triangle is 15 sq.units


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