Find the area of the triangle with vertices at the points:
(0, 0) (6, 0) and (4, 3)
Given: – Vertices of the triangle:
(0, 0) (6, 0) and (4, 3)
We know that,
If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:
Now, substituting given value in above formula
Expanding along R1
= 9 sq.units
Thus area of triangle is 9 sq.units