Find the area of the triangle with vertices at the points:

(0, 0) (6, 0) and (4, 3)


Given: – Vertices of the triangle:


(0, 0) (6, 0) and (4, 3)


We know that,


If vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:



Now, substituting given value in above formula



Expanding along R1





= 9 sq.units


Thus area of triangle is 9 sq.units


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