Using determinants, find the equation of the line joining the points
(1, 2) and (3, 6)
Given: – (1, 2) and (3, 6) are collinear points
Tip: – For Three points to be collinear, the area of the triangle formed by these points will be zero
Now, we know that,
Vertices of a triangle are (x1,y1), (x2,y2) and (x3,y3), then the area of the triangle is given by:
Now,
Let, 3rd point be (x,y)
Substituting given value in above formula
⇒
Expanding along R1
⇒
⇒ [x(– 4) – y(– 2) + 1(0)] = 0
⇒ – 4x + 2y = 0
⇒ y = 2x
It’s the equation of line