A 1.2 m tall girl spots a balloon movingwith the wind in a horizontal line at aheight of 88.2 m from the ground. Theangle of elevation of the balloon fromthe eyes of the girl at any instant is60°. After some time, the angle ofelevation reduces to 30° (see Fig. 9.13).Find the distance travelled by theballoon during the interval.
From this figure:
BF = 1.2 m,
AG = 88.2 m,
AC = AG – GC
= 88.2 – 1.2
= 87 m
∠EBD = 30° and ∠ABC = 60°,
CD = ?
In Δ ABC;
In Δ ABC,
Now, the distance covered by the balloon will be:
CD = BD – BC
CD =
CD = 5