|A| =
= 2(8 – 7) – 3(6 – 3) + 1(21 – 12)
= 2 – 9 + 9
= 2
Hence, A – 1 exists
Cofactors of A are:
C11 = 1 C21 = 1 C31 = – 1
C12 = – 3 C22 = 1 C32 = 1
C13 = 9 C23 = – 5 C33 = – 1
adj A =
=
So, adj A =
Now, A – 1 =
Also, A – 1.A =
=
=
Hence, A – 1.A = I