Find the inverse of each of the following matrices and verify that A – 1 A = I3.


|A| =


= 2(8 – 7) – 3(6 – 3) + 1(21 – 12)


= 2 – 9 + 9


= 2


Hence, A – 1 exists


Cofactors of A are:


C11 = 1 C21 = 1 C31 = – 1


C12 = – 3 C22 = 1 C32 = 1


C13 = 9 C23 = – 5 C33 = – 1


adj A =


=


So, adj A =


Now, A – 1 =


Also, A – 1.A =


=


=


Hence, A – 1.A = I


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