|A| = ![]()
= 2(8 – 7) – 3(6 – 3) + 1(21 – 12)
= 2 – 9 + 9
= 2
Hence, A – 1 exists
Cofactors of A are:
C11 = 1 C21 = 1 C31 = – 1
C12 = – 3 C22 = 1 C32 = 1
C13 = 9 C23 = – 5 C33 = – 1
adj A = 
= 
So, adj A = 
Now, A – 1 = 
Also, A – 1.A = 
= 
= 
Hence, A – 1.A = I