Solve the following pair of linear equations by the substitution and cross-multiplication methods:

8x + 5y = 9

3x + 2y = 4

8x + 5y = 9........(i)

3x + 2y = 4........(ii)

From equation (ii), we get

....... (iii)

Substituting this value in equation (i), we obtain

32 - 16y + 15y = 27

-y = -5

Y = 5............. (iv)

Substituting this value in equation (ii), we obtain

3x + 10 = 4

x = -2

Hence, x = -2, y =5

Again, by cross-multiplication method, we obtain

8x + 5y - 9 =0

3x + 2y - 4 = 0

x = -2 and y = 5