Solve the following pair of linear equations by the substitution and cross-multiplication methods:

8x + 5y = 9


3x + 2y = 4


8x + 5y = 9........(i)

3x + 2y = 4........(ii)


From equation (ii), we get


....... (iii)


Substituting this value in equation (i), we obtain



32 - 16y + 15y = 27


-y = -5


Y = 5............. (iv)


Substituting this value in equation (ii), we obtain


3x + 10 = 4


x = -2


Hence, x = -2, y =5


Again, by cross-multiplication method, we obtain


8x + 5y - 9 =0


3x + 2y - 4 = 0





x = -2 and y = 5


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