If 
find 
at 
We are given with an equation y = {logcosxsinx} {logsinxcosx} – 1 + sin – 1(
), we have to find 
at
x = 
by using the given equation, so by differentiating the equation on both sides with respect to x, we get,
By using the properties of logarithms,
y = {logcosxsinx}2 + sin – 1(
)
y = {
}2 + sin – 1(
)
= 2{
} 
= 2{
} 
= 2{
} 
Now putting the value of x = 
in the derivative solved above, we get,
(x = π/4) = 2{1} 
+ 
(x = π/4) = 2{1} 
+ 
(x = π/4) = 2{1} 
+ 
(x = π/4) = 
+ 
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