Find the equation of the plane determined by the intersection of the lines 
and 
Let L 1: 
and
L2 :
be the equations of two lines
Let the plane be ax + by + cz + d = 0 …… (1)
Given that the required plane through the intersection of the lines L1 and L2
Hence the normal to the plane is perpendicular to the lines L1 and L2
3a – 2b + 6c = 0
a – 3b + 2c = 0
Using cross multiplication, we get
7