Find , when
y = xcos x + (sin x)tan x
let y = xcos x + (sin x)tan x
⇒ y = a + b
where a= xcos x ; b = (sin x)tan x
a= xcos x
Taking log both the sides:
⇒ log a= log (x)cos x
⇒ log a= cos x log x
{log xa = alog x}
Differentiating with respect to x:
b = (sin x)tan x
Taking log both the sides:
⇒ log b= log (sin x)tan x
⇒ log b= tan x log (sin x)
{log xa = alog x}
Differentiating with respect to x: