If y = , show that
.
Basic idea:
√Second order derivative is nothing but derivative of derivative i.e.
√The idea of chain rule of differentiation: If f is any real-valued function which is the composition of two functions u and v, i.e. f = v(u(x)). For the sake of simplicity just assume t = u(x)
Then f = v(t). By chain rule, we can write the derivative of f w.r.t to x as:
√Product rule of differentiation-
√Apart from these remember the derivatives of some important functions like exponential, logarithmic, trigonometric etc..
Let’s solve now:
Given, y = …..equation 1
As we have to prove : ..
We notice a second-order derivative in the expression to be proved so first take the step to find the second order derivative.
Let’s find
As
So, lets first find dy/dx and differentiate it again.
As y is the product of two functions u and v
Let u = log x and v = 1/x
Using product rule of differentiation:
[∵ log x) =
&
]
Again using the product rule to find :
[∵ log x) =
&
]
∴ ….. proved