If y = sin (sin x), prove that : 
Given,
y = sin (sin x) ……equation 1
To prove: 
We notice a second-order derivative in the expression to be proved so first take the step to find the second order derivative.
Let’s find ![]()
As ![]()
So, lets first find dy/dx
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Using chain rule, we will differentiate the above expression
Let t = sin x ⟹ ![]()
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…….equation 2
Again differentiating with respect to x applying product rule:
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Using chain rule again in the next step-
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[using equation 1 : y =sin (sin x)]
And using equation 2, we have:
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