The volume of metal in a hollow sphere is constant. If the inner radius is increasing at the rate of 1 cm/sec, find the rate of increase of the outer radius when the radii are 4 cm and 8cm respectively.
Let the inner radius be r, outer radius be R and volume be V of a hollow sphere at any instant of time
We know the volume of the hollow sphere is
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Differentiating the volume with respect to time, we get

This is the rate of the volume of the hollow sphere and it is given this is constant hence
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Given that the rate of increase in inner radius of the hollow sphere,
, So the above equation becomes,
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So when the radii are 4cm and 8 cm, the above equation becomes,
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Therefore the rate of increase of the outer radius when the radii are 4 cm and 8cm respectively is 0.25 cm/sec