Find the The Slopes of the tangent and the normal to the following curves at the indicated points :
y = x3 – x at x = 2
Given:
y = x3 – x at x = 2
First, we have to find of given function, f(x),i.e, to find the derivative of f(x)
(xn) = n.xn – 1
The Slope of the tangent is
⇒ y = x3 – x
(x3) + 3
(x)
= 3.x3 – 1 – 1.x1 – 0
= 3x2 – 1
Since, x = 2
x = 2 = 3
(2)2 – 1
x = 2 = (3
4) – 1
x = 2 = 12 – 1
x = 2 = 11
The Slope of the tangent at x = 2 is 11
⇒ The Slope of the normal =
⇒ The Slope of the normal =
⇒ The Slope of the normal =