Draw a rough sketch of the graph of the curve and evaluate the area of the region under the curve and above the x - axis

Given equations are:

...... (1)

And x - axis ...... (2)

equation (1) represents an eclipse that is symmetrical about the x - axis and also about the y - axis, with center at origin and passes through (±2, 0) and (0, ±3).

A rough sketch is given as below: -

We have to find the area of shaded region.

Required area

= shaded region ABCA

= 2 (shaded region OBCO) ( as it is symmetrical about the x - axis)

(the area can be found by taking a small slice in each region of width Δx, then the area of that sliced part will be yΔx as it is a rectangle and then integrating it to get the area of the whole region)

(As x is between (0,2) and the value of y varies)

(as )

Substitute

So the above equation becomes,

We know,

So the above equation becomes,

Apply reduction formula:

On integrating we get,

Undo the substituting, we get

On applying the limits we get,

Hence the area of the region under the given curve and above the x - axis is equal to square units.