A and B are two independent events. The probability that A and B occur is 1/6 and the probability that neither of them occurs is 1/3. Find the probability of occurrence of two events.
P(A∩B)=
6P(A)2–5P(A)+1=0
6P(A)2–3P(A)–2P(A)+1=0
[2P(A)–1][3P(A)–1]=0
2P(A)–1=0
2P(A)=1
3P(A)–1=0
3P(A)=1