Construct the following quadrilaterals

(i) Quadrilateral ABCD


AB = 4.5 cm


BC = 5.5 cm


CD = 4 cm


AD = 6 cm


AC = 7 cm


(ii) Quadrilateral JUMP


JU = 3.5 cm


UM = 4 cm


MP = 5 cm


PJ = 4.5 cm


PU = 6.5 cm


(iii) Parallelogram MORE


OR = 6 cm


RE = 4.5 cm


EO = 7.5 cm


(iv) Rhombus BEST


BE = 4.5 cm


ET = 6 cm


(i) The rough sketch of this quadrilateral:


(a) ΔABC can be constructed as follows:



(b) Vertex D is 6 cm away from vertex A.


Hence, while taking A as centre, draw an arc of radius 6 cm



(c) Taking C as centre, draw an arc of radius 4 cm which cuts the previous arc at point D. Now, Join D to A and C



ABCD is the required quadrilateral


(ii) The rough sketch of this quadrilateral:



(a) Δ JUP can be constructed as follows:



(b) Vertex M is 5 cm away from vertex P and 4 cm away from vertex U


Now, Taking P and U as centers draw arcs of radii 5 cm and 4 cm respectively. Let the point of intersection be M



(c) Now, Join M to P and U



Hence, JUMP is the required quadrilateral


(iii) As we all know that opposite sides of a parallelogram are not only equal in length but also are parallel to each other


Therefore,


ME = OR,


MO = ER


The rough sketch of this parallelogram:



(a) Δ EOR can be constructed as follows:



(b) Vertex M is 4.5 cm away from vertex O and 6 cm away from vertex E. Hence, while taking O and E as centers, draw arcs of 4.5 cm radius and 6 cm radius respectively


Let, these will intersect each other at point M



(c) Join M to O and E



Therefore, MORE is the required parallelogram


(iv) As we all know that all sides of a rhombus are of the same measure


Therefore,


BE = ES = ST = TB


A rough sketch of this rhombus is as follows:



(a) Δ BET can be constructed as follows:



(b) Vertex S is 4.5 cm away from vertex E and also from vertex T.


Hence, taking E and T as centers, draw arcs of 4.5 cm radius, which will intersect each other at point S



(c) Join these intersected arcs, we will get the required rhombus



1
1