Construct an isosceles triangle whose base is 3.2 cm and altitude 1.7 cm and then construct another triangle whose sides are 
times the corresponding sides of the isosceles triangle.
Step1: Draw the base of triangle AB = 3.2 cm
Step2: Using scale mark the centre of AB as M and from M using protractor draw a line perpendicular to AB
Step3: Take distance 1.7 cm in compass keep the needle of the compass on point M and mark an arc intersecting ray drawn in step2. Mark the intersection point as C and join AC and BC.
Step4: Draw a ray at any angle below AB from A
The scaling factor is
Step5: Take any distance in compass and keeping the needle of the compass on point A cut an arc on ray constructed in step4 and name that point X1. Keeping the distance in compass same keep the needle of the compass on point X1 and cut an arc on the same ray and mark that point as X2. Draw 3 such parts (greater of 3 and 2 in 3/2), i.e. by repeating this process mark points upto X3
Step6: Join X2 and B (2 being smaller of 3 and 2 in 
and not X3 because the ratio 
is greater than 1)
Step7: Now extend AB and draw a line parallel to X2B from X3 intersecting AB at D
Step8: Extend AC and draw a line parallel to BC from point D intersecting AC at E and ΔADE whose sides are 
i.e. 1 1/2 times ΔABC is ready
