While multiplying B and 5 we are getting a number whose ones digit is B again.

This is only possible when B = 5 or B = 0


In that case,


The product will be, B × 5 = 5 × 5 = 25


2 will be a carry for the next step


Now,


We have, 5 × A + 2 = CA, which is possible for A = 2 or 7


The multiplication is as follows:



If B = 0,


B × 5 = B


0 × 5


= 0


There will not be any carry in this step.


In the next step, 5 × A = CA


It can only happen when A = 5 or A = 0


But, A cannot be 0 as AB is a two-digit number


Hence, A can be 5 only.


The multiplication is as follows:



Hence, there are 3 possible values of A, B, and C:


(i) 5, 0, and 2 respectively


(ii) 2, 5, and 1 respectively


(iii) 7, 5, and 3 respectively


6
1