Show that.

(i)


(ii)


(iii)


(iv)


(v)


(i) First Find the value of LHS



Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(i)


On Adding in eqn (i), we get




First Find the value of RHS



Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(i)


Therefore from eqn (i) and equ (ii) we found that LHS = RHS


(ii) First Find the value of LHS



Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(i)


On Adding in eqn (i), we get




First Find the value of RHS



Using Identity (a + b)2 = a2 + 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(ii)


Therefore from eqn (i) and equ (ii) we found that LHS = RHS


(iii) First Find the value of LHS



Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(i)


On Adding in eqn (i), we get




Therefore we found that LHS = RHS


(iv) First Find the value of LHS



Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(i)


Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of


In the given expression a =


On substituting these values in the above identity, we get



………………………………………………..(ii)


On subtracting eqn (ii) from eqn (i), we get





Therefore we found that LHS = RHS


(v) Using Identity (a + b)(a - b) = a2 - b2


In the given expression a =


On substituting these values in the above identity, we get


……………………………………………………….(i)


On substituting these values in (b - c) (b + c), we get


……………………………………………………….(ii)


On substituting these values in (c - a) (c + a), we get


……………………………………………………….(iii)


On adding eqn (i), (ii) and (iii), we get



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