Show that.
(i) 
(ii) 
(iii) 
(iv) 
(v) 
(i) First Find the value of LHS
Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(i)
On Adding 
in eqn (i), we get
First Find the value of RHS
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(i)
Therefore from eqn (i) and equ (ii) we found that LHS = RHS
(ii) First Find the value of LHS
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(i)
On Adding 
in eqn (i), we get
First Find the value of RHS
Using Identity (a + b)2 = a2 + 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(ii)
Therefore from eqn (i) and equ (ii) we found that LHS = RHS
(iii) First Find the value of LHS
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(i)
On Adding 
in eqn (i), we get
Therefore we found that LHS = RHS
(iv) First Find the value of LHS
Using Identity (a + b) 2 = a2 + 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(i)
Using Identity (a - b) 2 = a2 - 2ab + b2 for finding the value of 
In the given expression a = 
On substituting these values in the above identity, we get
⇒ 
………………………………………………..(ii)
On subtracting eqn (ii) from eqn (i), we get
Therefore we found that LHS = RHS
(v) Using Identity (a + b)(a - b) = a2 - b2
In the given expression a = 
On substituting these values in the above identity, we get
……………………………………………………….(i)
On substituting these values in (b - c) (b + c), we get
……………………………………………………….(ii)
On substituting these values in (c - a) (c + a), we get
……………………………………………………….(iii)
On adding eqn (i), (ii) and (iii), we get
