Use a single graph paper and draw the graph of the following equations. Obtain the vertices of the triangle so formed:
2y – x = 8
5y – x = 14
y – 2x = 1
The given equation is
– x + 2y = 8
– x + 5y = 14
and – 2x + y = 1
Now, let us find atleast two solutions of each of the above equations, as shown in the following tables.
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The coordinates of the vertices of ∆PQR are P( – 4, 2), Q(2, 5)and R(1, 3)