Evaluate the following integrals:
Assume, 2x2 + 3x + 1 = t
d(x2 + x + 1) = dt
(4x + 3)dx = dt
Substituting t and dt in above equation we get
⇒
But t = 2x2 + 3x + 1
⇒ 2(2x2 + 3x + 1)1/2 + c.