Solve each of the following initial value problems:
, y(0) = 0
, y(0) = 0
Given
and y(0) = 0
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This is a first order linear differential equation of the form
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Here,
and ![]()
The integrating factor (I.F) of this differential equation is,
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We have ![]()
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Hence, the solution of the differential equation is,
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We know ![]()
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However, when x = 0, we have y = 0
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⇒ 0 = (0 + c)e0
⇒ 0 = (c) × 1
∴ c = 0
By substituting the value of c in the equation for x, we get
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Thus, the solution of the given initial value problem is ![]()