Solve each of the following initial value problems:
, 
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Given
and ![]()
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This is a first order linear differential equation of the form
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Here, P = cot x and Q = 4x cosec x
The integrating factor (I.F) of this differential equation is,
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We have ![]()
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∴ I.F = sin x [∵ elog x = x]
Hence, the solution of the differential equation is,
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Recall ![]()
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⇒ y sin x = 2x2 + c
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∴ y = (2x2 + c) cosec x
However, when
, we have y = 0
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By substituting the value of c in the equation for y, we get

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Thus, the solution of the given initial value problem is ![]()