Solve the following quadratic equations:
Given 
= 0
Recall that the roots of quadratic equation ax2 + bx + c = 0, where a ≠ 0, are given by
Here, a = 1, 
and 
By substituting i2 = –1 in the above equation, we get
We can write 
[∵ i2 = –1]
[∵ (a – b)2 = a2 – 2ab + b2]
By using the result
, we get
[∵ i2 = –1]
Thus, the roots of the given equation are
and
.
2