Let f, g be two real functions defined by
and
. Then, describe each of the following functions.
i. f + g
ii. g – f
iii. fg
iv. 
v. 
vi. ![]()
vii. f2 + 7f
viii. 
Given
and ![]()
We know the square of a real number is never negative.
Clearly, f(x) takes real values only when x + 1 ≥ 0
⇒ x ≥ –1
∴ x ∈ [–1, ∞)
Thus, domain of f = [–1, ∞)
Similarly, g(x) takes real values only when 9 – x2 ≥ 0
⇒ 9 ≥ x2
⇒ x2 ≤ 9
⇒ x2 – 9 ≤ 0
⇒ x2 – 32 ≤ 0
⇒ (x + 3)(x – 3) ≤ 0
⇒ x ≥ –3 and x ≤ 3
∴ x ∈ [–3, 3]
Thus, domain of g = [–3, 3]
i. f + g
We know (f + g)(x) = f(x) + g(x)
![]()
Domain of f + g = Domain of f ∩ Domain of g
⇒ Domain of f + g = [–1, ∞) ∩ [–3, 3]
∴ Domain of f + g = [–1, 3]
Thus, f + g : [–1, 3] → R is given by ![]()
ii. f – g
We know (f – g)(x) = f(x) – g(x)
![]()
Domain of f – g = Domain of f ∩ Domain of g
⇒ Domain of f – g = [–1, ∞) ∩ [–3, 3]
∴ Domain of f – g = [–1, 3]
Thus, f – g : [–1, 3] → R is given by ![]()
iii. fg
We know (fg)(x) = f(x)g(x)
![]()
![]()
![]()
![]()
![]()
As earlier, domain of fg = [–1, 3]
Thus, f – g : [–1, 3] → R is given by ![]()
iv. ![]()
We know ![]()
![]()

As earlier, domain of
= [–1, 3]
However,
is defined for all real values of x ∈ [–1, 3], except for the case when 9 – x2 = 0 or x = ±3
When x = ±3,
will be undefined as the division result will be indeterminate.
⇒ Domain of
= [–1, 3] – {–3, 3}
∴ Domain of
= [–1, 3)
Thus,
: [–1, 3) → R is given by ![]()
v. ![]()
We know ![]()


As earlier, domain of
= [–1, 3]
However,
is defined for all real values of x ∈ [–1, 3], except for the case when x + 1 = 0 or x = –1
When x = –1,
will be undefined as the division result will be indeterminate.
⇒ Domain of
= [–1, 3] – {–1}
∴ Domain of
= (–1, 3]
Thus,
: (–1, 3] → R is given by ![]()
vi. ![]()
We know (f – g)(x) = f(x) – g(x) and (cf)(x) = cf(x)
![]()
![]()
As earlier, Domain of
= [–1, 3]
Thus,
: [–1, 3] → R is given by ![]()
vii. f2 + 7f
We know (f2 + 7f)(x) = f2(x) + (7f)(x)
⇒ (f2 + 7f)(x) = f(x)f(x) + 7f(x)
![]()
![]()
Domain of f2 + 7f is same as domain of f.
∴ Domain of f2 + 7f = [–1, ∞)
Thus, f2 + 7f : [–1, ∞) → R is given by ![]()
viii. ![]()
We know
and (cg)(x) = cg(x)
![]()
Domain of
= Domain of g = [–3, 3]
However,
is defined for all real values of x ∈ [–3, 3], except for the case when 9 – x2 = 0 or x = ±3
When x = ±3,
will be undefined as the division result will be indeterminate.
⇒ Domain of
= [–3, 3] – {–3, 3}
∴ Domain of
= (–3, 3)
Thus,
: (–3, 3) → R is given by ![]()